A 3.00-kilogram mass is thrown vertically upward with an initial speed of 9.80 meters per second. What is the maximum height this object will reach?

Answer 1

4.895m

Since it is moving upward, a = -9.81 m/s^2 Here, u = 9.80 m/s. At its maximum height, v = 0 m/s. Using the formula v^2 = u^2 + 2ax, compute x 0 = 9.80^2 + 2 (-9.81) x x = 96.04/19.62 x = 4.895 m.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Carson Alexander

Use the kinematic equation: ( h = \frac{v_0^2}{2g} ), where ( h ) is the maximum height, ( v_0 ) is the initial velocity, and ( g ) is the acceleration due to gravity. Plug in the values: ( h = \frac{9.8^2}{2 \times 9.8} ). The maximum height is 4.9 meters.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.