# A 2000 Ltank containing 550 L of water is being filled with water at the rate of 75 L per minute from a full 1600 L tank. How long will it be before the two tanks have the same amount of water?

7 minutes

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To find out when the two tanks will have the same amount of water, we need to calculate the rate at which the second tank is being filled. Since the second tank is being filled at a rate of 75 L per minute, the difference in volume between the two tanks is decreasing by 75 L per minute.

The initial difference in volume between the two tanks is 2000 L - 550 L = 1450 L.

To find out how long it takes for the two tanks to have the same amount of water, we divide the initial difference in volume by the rate at which the difference is decreasing: 1450 L / 75 L/min = 19.33 minutes.

Therefore, it will take approximately 19.33 minutes before the two tanks have the same amount of water.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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