A 2000 Ltank containing 550 L of water is being filled with water at the rate of 75 L per minute from a full 1600 L tank. How long will it be before the two tanks have the same amount of water?

Question

Genesis Allen · Accepted Answer

7 minutes

2000 L tank contains 550 L water and another tank contains 1600 L water. Both tank's water will be equal when 2nd tank delivers water to 1st tank. The quantity of water will be delivered by 1st tank = #[1600+550]/2 - 550 = 525 L#. Time taken by 2nd tank to delivers the water = 525#-:#75 = 7 minutes

Savannah Anderson · Answer

undefined To find out when the two tanks will have the same amount of water, we need to calculate the rate at which the second tank is being filled. Since the second tank is being filled at a rate of 75 L per minute, the difference in volume between the two tanks is decreasing by 75 L per minute.

The initial difference in volume between the two tanks is 2000 L - 550 L = 1450 L.

To find out how long it takes for the two tanks to have the same amount of water, we divide the initial difference in volume by the rate at which the difference is decreasing:
1450 L / 75 L/min = 19.33 minutes.

Therefore, it will take approximately 19.33 minutes before the two tanks have the same amount of water.