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A 20% sugar solution has a volume of 500 mL. How many grams of sugar does it contain?

Answer 1

#154# grams, assuming that the sugar is pure glucose.

Well, the volume of the solution is #500 \ "mL"#, and #20%# of it is sugar, so the volume of sugar in the solution is:

#500 \ "mL"*20%=100 \ "mL"#

Now, I assume the sugar to be pure glucose #(C_6H_12O_6)#. To find the mass of sugar, we have to multiply the volume of the sugar found by its density.

Glucose has a density of #1.54 \ "g/cm"^3#. Note that #1 \ "cm"^3-=1 \ "mL"#, so the density of glucose can also be written as #1.54 \ "g/mL"#.

Therefore, the mass of sugar found in this solution will be:

#100color(red)cancelcolor(black)"mL"*(1.54 \ "g")/(color(red)cancelcolor(black)"mL")=154 \ "g"#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.