A 10 kg mass has a KE of 125 J, what is its velocity?

Answer 1

Amelia Adams

5 m/s

#EK = 1/2 mv^2#

Given: #EK = 125J= 125 kgm^2/s^2, m = 10kg#

So #v^2 = (2EK)/m# and #v = sqrt ((2EK)/m)#

#v = sqrt((2*125(kgm^2)/s^2)/(10kg)) = sqrt(25m^2/s^2) = 5 m/s#

To help avoid mistakes, I solve the units first.

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Answer 2

Leo Abeyta

The velocity of the 10 kg mass can be calculated using the kinetic energy formula: ( KE = \frac{1}{2} mv^2 ), where ( m ) is the mass and ( v ) is the velocity.

Rearranging the formula to solve for velocity:

( v = \sqrt{\frac{2KE}{m}} )

Substituting the given values:

( v = \sqrt{\frac{2 \times 125 , \text{J}}{10 , \text{kg}}} )

( v = \sqrt{25} , \text{m/s} )

( v = 5 , \text{m/s} )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.