A 0.0245 mg sample of nitrogen reacts with oxygen to form 0.0945 mg of the oxide. What is the empirical formula of this nitrogen oxide compound?

Answer 1

The empirical formula is #"N"_2"O"_5#.

The reaction's equation is

#A_"r":color(white)(mmmll)14.01color(white)(mml)16.00# #color(white)(mmmmmll)x"N"_2color(white)(m) + color(white)(ll) y"O"_2 → 2"N"_x"O"_y"# #"Mass/µg":color(white)(m)24.5color(white)(mmm)70.0"color(white)(mml)94.5#
First, we must calculate the masses of #"N"# and #"O"# from the mass of the oxide.
#"Mass of N in oxide = 24.5 µg"#
#"Mass of O in oxide" = "mass of oxide - mass of N" = "(94.5 - 24.5) µg" = "70.0 µg"#

We now need to find the ratios of these masses after converting them to moles.

I like to compile the calculations into a table from this point on.

#ul(bb("Element"color(white)(X) "Mass/µg"color(white)(X) "Amt/µmol"color(white)(m) "Ratio"color(white)(ml)×2color(white)(mm)"Integers"))# #color(white)(mm)"N"color(white)(mmmml)24.5color(white)(mmmmll)1.748color(white)(Xmm)1color(white)(mmml)2color(white)(Xmmml)2# #color(white)(mm)"O" color(white)(XXXml)70.0 color(white)(mmmmll)4.375 color(white)(mmm)2.502 color(white)(ml)5.004color(white)(Xml)5#
The empirical formula is #"N"_2"O"_5#.
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Answer 2

Calculate moles of nitrogen and oxygen. Determine the mole ratio. Empirical formula: N₂O.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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