84.27 grams of hexane combusts with excess oxygen to form carbon dioxide and water. What mass of water in grams will be produced?

Answer 1

The reaction will produce 123.4 g of water.

  1. Write the equation that is balanced.
#"2C"_6"H"_14 + "19O"_2 → "12CO"_2 + "14H"_2"O"#
2. Calculate the moles of #"C"_6"H"_14#.
#"Moles of C"_6"H"_14 = 84.27 color(red)(cancel(color(black)("g C"_6"H"_14))) × ("1 mol C"_6"H"_14)/(86.17 color(red)(cancel(color(black)("g C"_6"H"_14)))) = "0.977 95 mol C"_6"H"_14"#
3. Calculate the moles of #"H"_2"O"#.
#"Moles of H"_2"O" = "0.977 95" color(red)(cancel(color(black)("mol C"_6"H"_14))) × ("14 mol H"_2"O")/(2 color(red)(cancel(color(black)("mol C"_6"H"_14)))) = "6.8457 mol H"_2"O"#
4. Calculate the mass of #"H"_2"O"#.
#"Mass of H"_2"O" = 6.8457 color(red)(cancel(color(black)("mol H"_2"O"))) × ("18.02 g H"_2)/(1 color(red)(cancel(color(black)("mol H"_2"O")))) = "123.4 g H"_2"O"#
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Answer 2

The mass of water produced will be 72 grams.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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