How could #"zinc chloride"# be prepared?

Question

Luna Chen · Accepted Answer

Zinc metal and chlorine gas....

And we can represent this by the redox reaction.... #Zn(s) + Cl_2(g) stackrel(Delta)rarrZnCl_2(s)# The metal is oxidized, and chlorine gas is reduced..... Of course you could oxidize the metal by the action of hydrochloric acid... #Zn(s) + 2HCl(aq) rarr ZnCl_2(aq) +H_2(g)uarr#

Caleb Adams · Answer

FIRST, you need anything that contains either zinc and/or chloride.  Then you need to make sure that they will combined to give you a product of #ZnCl_2#. The easiest one would be to just dissolve zinc metal in hydrochloric acid:
#Zn + 2HCl -> ZnCl_2 + H_2 (g)#

Owen Ambrose · Answer

See below:

A safe and easy method is to choose a suitable base such as zinc oxide or zinc carbonate. XS base is added to dilute hydrochloric acid. The mixture is filtered and the zinc chloride solution is crystallised. #sf(ZnO_((s))+2HCl_((aq))rarrZnCl_(2(aq))+H_2O_((l))# or #sf(ZnCO_(3(s))+2HCl_((aq))rarrZnCl_(2(aq))+CO_(2(g))+H_2O_((l)))#

Luna Chen · Answer

undefined Zinc chloride can be prepared by dissolving zinc oxide or zinc metal in hydrochloric acid. The equation for the reaction is:

ZnO(s) + 2HCl(aq) → ZnCl2(aq) + H2O(l)

Alternatively:

Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)

In both cases, zinc chloride is formed along with water or hydrogen gas as a byproduct.