How many oxygen ATOMS are present in a #28.9*g# mass of #"dioxygen"#?

Answer 1

Approx. #1xx10^24*"oxygen atoms"#

We take the molar quantity of dioxygen....

#=(28.9*g)/(32.00*g*mol^-1)=0.903*mol# with respect to #O_2#..
And then we multiply this by the #"Avocado number"#, the number of avocadoes in a mole of avocadoes....
#=0.903*molxx6.022xx10^23*mol^-1=5.44xx10^23*"oxygen molecules"#

...but NOTE we were asked for the number of oxygen atoms....and CLEARLY this is TWICE the number of oxygen molecules. Capisce?

And thus.....

#5.44xx10^23*"oxygen molecules"xx2*"oxygen atoms molecule"^-1#
#=" how many oxygen atoms"#....
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Answer 2

There are approximately ( 4.525 \times 10^{23} ) oxygen atoms present in a 28.9 g mass of dioxygen.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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