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Can you represent the reaction of hydrogen sulfide with sulfur dioxide to give water and elemental sulfur by means of a chemical equation?

Answer 1

Wyatt Atkins

#2H_2S(g) + SO_2(g)rarr 3S(s) + 2H_2O(l)#

This is a #"comproportionation reaction"# in which sulfur is both reduced and oxidized....

#"Oxidation,"# #S(-II)rarrS(+IV)# #H_2S(g) +2H_2O(l) rarr SO_2(g)+6H^+ +6e^(-)# #(i)#

#"Reduction,"# #S(+IV)rarrS(0)# #SO_2(g) +4H^+ +4e^(-)rarr S(s)+2H_2O(l) # #(ii)#

And so we add #2xx(i)+3xx(ii):#

#2H_2S(g) +cancel(4H_2O(l)) +cancel(3)2SO_2(g) +cancel(12)6H^+ +cancel(12e^(-))rarr cancel(SO_2(g))+3S(s)+cancel(6)2H_2O(l) +cancel(6H^+) +cancel(12e^(-))#

#2H_2S(g) +2SO_2(g) rarr 3S(s)+2H_2O(l) #

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Answer 2

Xavier Avery

Sure, the chemical equation representing the reaction of hydrogen sulfide ((H_2S)) with sulfur dioxide ((SO_2)) to give water ((H_2O)) and elemental sulfur ((S)) is:

[ 2H_2S + 3SO_2 \rightarrow 2H_2O + 3S ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.