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What mass of sodium hydroxide is present in a #40%# #"m/m"# solution of #"sodium hydroxide"#?

Answer 1

Naomi Aronson

Unknown on these data....we need the density of the solution....

We gots a #40%# solution of sodium hydroxide in water....

i.e. #"mass of sodium hydroxide"/"mass of solution"xx100%=40%#

We need the density of the solution to approach its concentration in #"moles per litre"#.

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Answer 2

Owen Ambrose

To calculate the mass of sodium hydroxide present in a 40% mass/mass (m/m) solution of sodium hydroxide, you would multiply the total mass of the solution by the percentage of sodium hydroxide.

Let's say you have 100 grams of the solution (since percentages are often calculated per 100 grams). To find the mass of sodium hydroxide in this solution:

[ \text{Mass of sodium hydroxide} = \text{Total mass of solution} \times \text{Percentage of sodium hydroxide} ]

[ \text{Mass of sodium hydroxide} = 100 , \text{g} \times 0.40 ]

[ \text{Mass of sodium hydroxide} = 40 , \text{g} ]

So, in a 40% m/m solution of sodium hydroxide, 40 grams of sodium hydroxide are present in 100 grams of the solution.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.