Daniel spent #4/6# of his pocket money in one day. If he spent #$138# on that day, how much money did he start with?

Answer 1

The whole is 207.

Let the whole be x.

#138=4/6x#
#828=4x#
#207=x#
#x=207#
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Answer 2

#207#

You are comparing #4/6# with #6/6# which is the whole.
If #138# represents #4# parts, then how much represents #6# parts.
#138/x = 4/6" "larr# cross multiply
#4x = 138xx6#
#x = (138xx6)/4#
#x = 207#
YOu can also increase #138# in the ratio #3:2#
#138 xx 3/2" " (4/6 = 2/3)#
#=207#
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Answer 3

To find out how much money Daniel started with, you can use the following equation:

( \text{Total pocket money} = \frac{\text{Amount spent}}{\text{Fraction spent}} )

Substitute the given values:

( \text{Total pocket money} = \frac{138}{\frac{4}{6}} )

Calculate the fraction:

( \frac{4}{6} = \frac{2}{3} )

Then:

( \text{Total pocket money} = \frac{138}{\frac{2}{3}} = 138 \times \frac{3}{2} )

( \text{Total pocket money} = 207 )

Therefore, Daniel started with $207.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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