# Solve the equation #x^2+5x+4 ge 0 #?

#x le -4# or#x ge -1#

We have:

We first solve the equation:

Ther using appropriate software or a graphical calculator we examine the graph: graph{ y=x^2+5x+4 [-10, 10, -5, 5]}

and we see from the graph that:

Thus we have:

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To solve the equation (x^2 + 5x + 4 \geq 0), first factor the quadratic expression: ((x + 1)(x + 4) \geq 0). Then, determine the intervals where the expression is greater than or equal to zero using the signs of the factors: (-4 \leq x \leq -1) and (x \geq -4). So, the solution is (x \in [-4, -1] \cup [-1, \infty)).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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