# How do you graph a circle a circle with a center at #(0, -6)# and a radius of 1?

See a solution process below:

The equation for a circle is:

We can rewrite the equation in the problem as:

graph{(x^2 + (y+6)^2 - 1)(x^2 + (y+6)^2 - 0.0025) = 0 [-5, 5, -8, -3]}

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- A triangle has corners at #(4 ,6 )#, #(2 ,9 )#, and #(8 ,4 )#. What is the area of the triangle's circumscribed circle?
- A circle has a center that falls on the line #y = 3/8x +8 # and passes through # ( 7 ,4 )# and #(2 ,9 )#. What is the equation of the circle?

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