What is the mass of #9.06xx10^23# #"sodium atoms"#?

Answer 1

Well, we know that the #"Avocado number"# #=# #6.022xx10^23*mol^-1#....

And so we take the quotient....

#(9.06xx10^23*"sodium atoms")/(6.022xx10^23*"sodium atoms"*mol^-1)=1.50*mol#

And thus since there are #1.50*mol# sodium atoms, there are #0.75*mol# with respect to #Na_2O#. Why did we divide the molar quantity with respect to sodium by 2?

What is the mass of this quantity of sodium oxide?

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Answer 2

Jeremiah Adams

The mass of (9.06 \times 10^{23}) sodium atoms can be calculated using the molar mass of sodium (Na), which is approximately (22.99 , \text{g/mol}).

(9.06 \times 10^{23}) sodium atoms correspond to (1 , \text{mole}) of sodium atoms.

Therefore, the mass of (9.06 \times 10^{23}) sodium atoms is approximately (22.99 , \text{grams}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.