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One litre of water contains #0.121*mol# of gold metal. How many atoms of gold are present?

Answer 1

Natalie Anton

An unfeasibly large number of gold atoms......

....and enuff to start a gold rush.

You have proposed that there are #0.121*mol# of gold in that volume. Setting aside reality there are....

#0.121*molxx6.022xx10^23*mol^-1=7.3xx10^22# #"individual atoms of gold"#.

Clearly you have made a mistake writing down the question. This happens.

What was that story about the beach in Alaska, tremendously inaccessible, and inhospitable, that was initially covered in gold. Was it Nome?

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Answer 2

Peyton Adams

To find the number of atoms of gold present, you need to use Avogadro's constant, which is (6.022 \times 10^{23}) atoms per mole.

Given that 1 liter of water contains 0.121 moles of gold, you can calculate the number of atoms by multiplying the number of moles by Avogadro's constant.

(0.121 \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mole} = 7.286 \times 10^{22}) atoms of gold.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.