If the mass of a single electron is #9.10938xx10^-31kg#, how many electrons constitute a mass of #1g#?

Answer 1

You could have quoted the #"electronic mass"#, ..........

Additionally, the mass of an electron is 9.10938x10^-31kg-= 9.10938x10^-28g.

Consequently, the electron count is.....

#(1.000*g)/(9.10938xx10^-28*g)=1.098xx10^27# #"individual electrons."#

And note that the charge of this quantity of electrons, i.e. #−1.602×10^(-19) C*"electron"^-1xx1.098xx10^27*"electron"# would be phenomenonally GREAT.

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Answer 2

Jose Ayala

To find out how many electrons constitute a mass of 1 gram, we can divide the mass of 1 gram by the mass of a single electron.

1 gram / (9.10938 × 10^-31 kg) ≈ 1.09776 × 10^30 electrons

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

If the mass of a single electron is #9.10938xx10^-31*kg#, how many electrons constitute a mass of #1*g#?

If the mass of a single electron is #9.10938xx10^-31kg#, how many electrons constitute a mass of #1g#?