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How many atoms in a mass of ONE MOLE of #"magnesium nitrate"#?

Answer 1

You have the formula #Mg(NO_3)_2#....

And so there are #1xxMg+2xxN+6xxO*"atoms"#.......

Additionally, we could figure out the nitrate's molar mass.

...which is #148.30*g*mol^-1#. And thus in #"Avogadro's number of magnesium nitrate formula units,"# #"i.e. a mass of 148.3 g"#, #N_A-=6.022xx10^23*mol^-1#, there are #1xxN_A(Mg) + 2xxN_A(N) + 6xxN_A(O)-=9N_A# atoms in toto....

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Answer 2

Ellie Andrews

The molecular formula of magnesium nitrate is Mg(NO3)2, which means that each formula unit contains one magnesium atom (Mg), two nitrogen atoms (N), and six oxygen atoms (O). Consequently, the total number of atoms in one mole of magnesium nitrate is: 1 (magnesium atom) + 2 (nitrogen atoms) + (6 * 3) (oxygen atoms) = 1 + 2 + 18 = 21 atoms.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.