Given a #3.00*g# mass of sodium metal, what mass of chlorine gas is equivalent? What mass of sodium chloride could be made given this quantity?

Answer 1

We assume a stoichiometric excess of chlorine gas......and we work out the mass of sodium chloride produced given 100% yield.

Additionally, a stoichiometric equation needs to be written.

#Na(s) + 1/2Cl_2(g) rarr NaCl(s)#

As stated, half an equivalent of (binculear) chlorine gas oxidizes sodium metal in this redox reaction.

#"Moles of natrium"=(3.00*g)/(22.99*g*mol^-1)=0.131*mol#
And thus we should get #0.131*mol# of salt.....i.e.
#0.131*molxx58.44*g*mol^-1=7.63*g#.
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Answer 2

To determine the mass of chlorine gas equivalent to 3.00 g of sodium, we need to use the stoichiometry of the reaction between sodium and chlorine gas. The balanced chemical equation for the reaction is:

[ 2 \text{Na} + \text{Cl}_2 \rightarrow 2 \text{NaCl} ]

This equation shows that 2 moles of sodium react with 1 mole of chlorine gas to produce 2 moles of sodium chloride.

First, we calculate the molar mass of sodium (Na) and chlorine (Cl₂):

  • Molar mass of Na: 22.99 g/mol
  • Molar mass of Cl₂: 35.45 g/mol

Next, we calculate the number of moles of Na in 3.00 g:

[ \text{Moles of Na} = \frac{\text{Mass of Na}}{\text{Molar mass of Na}} ]

Using the stoichiometry of the reaction, we find the moles of Cl₂ required:

[ \text{Moles of Cl}_2 = \frac{\text{Moles of Na}}{2} ]

Finally, we calculate the mass of Cl₂ in grams:

[ \text{Mass of Cl}_2 = \text{Moles of Cl}_2 \times \text{Molar mass of Cl}_2 ]

To determine the mass of sodium chloride (NaCl) that could be made from the reaction, we use the same stoichiometry:

[ \text{Moles of NaCl} = \frac{\text{Moles of Na}}{2} ]

Then, we calculate the mass of NaCl in grams:

[ \text{Mass of NaCl} = \text{Moles of NaCl} \times \text{Molar mass of NaCl} ]

The molar mass of NaCl is 58.44 g/mol (22.99 g/mol for Na + 35.45 g/mol for Cl).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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