# What mass of salt is contained in a #200*mL# volume of solution that is #0.10*mol*L^-1# with respect to #KCl(aq)#?

Approx.

And so we got a mass of.....

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To find the mass of salt (KCl) in the solution, we first need to calculate the number of moles of KCl present in the solution using the formula:

moles = concentration (mol/L) * volume (L)

Given: Concentration of KCl solution = 0.10 mol/L Volume of solution = 200 mL = 0.200 L

moles = 0.10 mol/L * 0.200 L moles = 0.020 mol

Now, we need to convert moles of KCl to grams using its molar mass. The molar mass of KCl is approximately 74.55 g/mol.

mass = moles * molar mass mass = 0.020 mol * 74.55 g/mol mass ≈ 1.49 g

Therefore, the mass of KCl contained in a 200 mL volume of 0.10 mol/L KCl solution is approximately 1.49 grams.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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