What molar quantity is present in a #0.5mL# of #5.0mol*L^-1# acetic acid?

Answer 1

Do you realize what you have asked....?

It seems like you just asked...

#"what is the volume of a 0.5 mL volume of acetic acid?"#

You may be interested in knowing how many moles of acetic acid are present in that volume. If so, since.....

#"Concentration"="Moles of solute"/"Volume of solution"#, we take the product.....#"moles"="concentration"xx"volume"#.....

#=0.5*cancel(mL)xx10^-3*cancel(L*mL^-1)xx5*mol*cancel(L^-1)=0.0025*mol#.

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Answer 2

Natalie Anton

Maybe: 100 mL

I don't think you ignore that "ml" in "0.5 ml" is the measure of volume. In this case, you don't want to search for the volume you already know.

As you mispelled "acitic" instead of acetic, your question makes sense if you also mispelled "ml" instead of "mol".

Thus, let us assume the right question is "How to find volume of 0.5 mol of 5M of acitic acid?

5M means 5 moles of acetic acid per liter of solution. If you want 0.5 moles, that is one tenth of 5 moles, you will take just one tenth of one liter, i.e. 0.1 L = 100 mL of that solution.

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Answer 3

Henry Antrim

The molar quantity present in 0.5 mL of 5.0 mol/L^-1 acetic acid is 0.0025 moles.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

What molar quantity is present in a #0.5*mL# of #5.0*mol*L^-1# acetic acid?

What molar quantity is present in a #0.5mL# of #5.0mol*L^-1# acetic acid?