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What is the concentration of a #1mL# volume of a solution of #37%# #HCl# #(rho=1.18gmL^-1)# that is diluted to #3.50mL#?

Answer 1

You really have not specified the boundary conditions of this problem correctly........

Now, I ASSUME that you have diluted a #1*mL# volume of #37%# #"w/w"# hydrochloric solution to #3.5*mL#. In order to calculate this problem you need the density of the conc. acid, which is #rho=1.18*g*mL^-1#. These data SHOULD have been included with the question.

So we want #"moles of solute"/"volume of solution"#

#=((1*mLxx1.18*g*mL^-1xx37%)/(36.46*g*mol^-1))/(3.5*cancel(mL)xx10^-3*L*cancel(mL^-1))=3.4*mol*L^-1#

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Answer 2

Serenity Allen

The concentration of the diluted solution would be 1.62 M.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

What is the concentration of a #1*mL# volume of a solution of #37%# #HCl# #(rho=1.18*g*mL^-1)# that is diluted to #3.50*mL#?

What is the concentration of a #1mL# volume of a solution of #37%# #HCl# #(rho=1.18gmL^-1)# that is diluted to #3.50mL#?