If the molar mass of a material is #147.01*g*mol^-1#, what mass of the material is required for a #1*L# volume of a #0.1*mol*L^-1# solution?

Answer 1

We use the definition of concentration......#"Concentration"="Moles"/"Volume"#.

And we get a required mass of #14.7*g#.

And thus #"moles"="volume"xx"concentration"#
We require.....#1*Lxx0.1*mol*L^-1=0.1*mol#.
And now we simply multiply this molar quantity by the molar mass, i.e. #0.1*molxx147.01*g*mol^-1=14.7*g#.....
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Answer 2

147.01 grams of the material are required for a 1 L volume of a 0.1 mol/L solution.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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