If the area of the base of a square pyramid is #169 ft^2#, what is the perimeter of the base?

Answer 1

#p = 52" ft"#

The area of the square base is:

#s^2 = 169" ft"^2#
where #s# is the length of the 4 equal sides.

Solve for s:

#s = sqrt169#
#s = 13" ft"#

The formula for the perimeter is:

#p = 4s#
#p = 4(13" ft")#
#p = 52" ft"#
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Answer 2

#P=52"ft"#

If the area of the base of the pyramid is #169"ft"^2# then each side of the base is #13"ft"# long because the base of the pyramid is a square.
Length of the side, # s= sqrt169 = 13#
Iif we take the area of a square #A=s^2# where #s=13# we get the area of the base to be #169"ft"^2# thus proving that each side of the base is #13"ft"# long.

So to find the perimeter of the base of the pyramid we use the formula:

#P=4s# where #s=13"ft"# and thus,
#p=4*13"ft"=52"ft"#
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Answer 3

The perimeter of the base of the square pyramid is 52 feet.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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