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What is the relative order of bond polarity, with respect to #N-H#, #O-H#, #F-H#, and #P-H#?

Answer 1

Caleb Adams

#underbrace(H-P, H-N, H-O, H-F)_rarr#
#"Order of increasing bond polarity......"#

And how to assess this quantitatively? Well, examine the Pauling electronegativities of #H(2.02); P(2.19); N(3.04); O(3.44); F(3.98)#

Clearly, #H-F# should give rise to the most polar bond.

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Answer 2

Caleb Adams

The relative order of bond polarity, from least to greatest, is P-H < N-H < O-H < F-H.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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