What is the percentage of oxygen in sulfuric acid?

Answer 1

The percentage of oxygen in sulfuric acid is 65.254%.

The chemical formula for sulfuric acid, #"H"_2"SO"_4#, indicates that in one mole of sulfuric acid, there are four moles of oxygen atoms. In order to calculate the percentage of oxygen in sulfuric acid, you need to divide the mass of oxygen in one mole of sulfuric acid by the molar mass of sulfuric acid and multiply by 100.

Molar mass #"H"_2"SO"_4="98.072 g/mol"#

Mass of O: #4xx"15.999 g/mol"="63.996 g/mol"#

The percentage O

#(63.996color(red)cancel(color(black)("g/mol")))/(98.072color(red)cancel(color(black)("g/mol")))xx100="65.254% O"#

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Answer 2

Jeremiah Adams

The molar mass of oxygen in sulfuric acid (H2SO4) is 16 g/mol, and the molar mass of sulfuric acid is 98.08 g/mol. Therefore, the percentage of oxygen in sulfuric acid is (4 * 16 g/mol / 98.08 g/mol) * 100 ≈ 65.3%. This calculation is done by finding the molar mass of the oxygen atoms in the compound, dividing it by the molar mass of the entire compound, and multiplying the result by 100 to obtain the percentage.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.