What is the mass of 500 molecules of #"NaCl"#?

Answer 1
There is no such thing as an ionic molecule, so I will instead calculate for #"500 formula units"#...
#"500 equiv. NaCl" xx ("1 mol")/(6.0221413 xx 10^(23) "things")#
#= 8.303 xx 10^(-22) "mols NaCl"#
(what is this #6.0221413 xx 10^(23)# number called?)
And each #"mol"# has a characteristic molar mass of #22.989 + 35.453 = "58.442 g"#, using the periodic table for #"Na"# and #"Cl"# (what are their names?).

As a result, the mass is:

#8.303 xx 10^(-22) cancel"mols NaCl" xx ("58.442 g")/(cancel"1 mol NaCl")#
#=# #ulcolor(blue)(4.852 xx 10^(-20) "g")#
Now, this number is absurdly small, but that should make sense, as we only have #500# particles, each a few nanometers in diameter, much, much less than a handful of salt formula units.
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Answer 2

To find the mass of 500 molecules of NaCl (sodium chloride), you first calculate the molar mass of NaCl, which is approximately 58.44 grams per mole. Then, you divide this molar mass by Avogadro's number (6.022 x 10^23) to find the mass of one molecule. Finally, multiply the mass of one molecule by 500 to get the total mass of 500 molecules of NaCl.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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