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How is a #35%# #"w/w"# solution of a #200*g# mass of sodium chloride in water prepared?

Answer 1

Olivia Anton

About #70*g# of salt, and #130*mL# water.........

#"Concentration"="Mass of solute"/"Mass of solute + mass of water"xx100%#

And thus #35%="Mass of solute"/(200*g)#....

And so #"mass of solute"-=35%xx200*g=70*g#.

And the volume of the solution would change only very marginally, even upon the addition of such a mass of solute.

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Answer 2

Avery Adams

To prepare a 35% "w/w" solution of a 200 g mass of sodium chloride in water, you would dissolve 35% of 200 g (which is 70 g) of sodium chloride in enough water to make a total mass of 200 g.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.