How many moles are present in a #1.50*L# volume of a semi-molar solution?

Answer 1

If you have a #1500*mL# of a #0.50*mol*L^-1# solution, you have #0.75*mol# in solution........

#"Molarity"="Concentration"="Moles of solute"/"Volume of solution"#
And of course #"Moles of solute"="Mass of solute"/"Molar mass of solute"#......
But we don't have the molar mass of the solute, and we are guessing that a #"semi molar solution"# #=# #0.50*mol*L^-1#.

We need more data please.......

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Answer 2

A semi-molar solution contains 0.5 moles of solute per liter of solution. Therefore, in a 1.50 L volume of this solution, there would be 0.5 * 1.50 = 0.75 moles of solute present.

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Answer 3

To find the number of moles present in a solution, you can use the formula:

moles = molarity × volume (in liters)

Given: Volume of solution = 1.50 L Molarity (semi-molar) = 0.5 mol/L

Using the formula:

moles = 0.5 mol/L × 1.50 L moles = 0.75 moles

Therefore, there are 0.75 moles present in a 1.50 L volume of a semi-molar solution.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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