How many moles are present in a #1.50*L# volume of a semi-molar solution?
If you have a
We need more data please.......
By signing up, you agree to our Terms of Service and Privacy Policy
A semi-molar solution contains 0.5 moles of solute per liter of solution. Therefore, in a 1.50 L volume of this solution, there would be 0.5 * 1.50 = 0.75 moles of solute present.
By signing up, you agree to our Terms of Service and Privacy Policy
To find the number of moles present in a solution, you can use the formula:
moles = molarity × volume (in liters)
Given: Volume of solution = 1.50 L Molarity (semi-molar) = 0.5 mol/L
Using the formula:
moles = 0.5 mol/L × 1.50 L moles = 0.75 moles
Therefore, there are 0.75 moles present in a 1.50 L volume of a semi-molar solution.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- A liquid has a molecular weight of 105.141g/mol. Its density is 1.173g/mL. What is the molarity of the pure liquid?
- If 16.0 mL of water are added to 31.5 mL M #Ba(OH)_2(aq)#, what is the new solution molarity?
- A #75*mL# volume of #0.211*mol*L^-1# #NaOH# was diluted to #125*mL#. What is the new concentration?
- A #25*mL# volume of sodium hydroxide solution of #0.150*mol*L^-1# concentration is stoichiometrically equivalent to a #15.0*mL# of sulfuric acid. What is #[H_2SO_4]#?
- How does dilution affect concentration?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7