When #"4 g H"_2# and #"32 g O"_2# are mixed, what is the partial pressure of oxygen at a total pressure of #P#?

Answer 1
About #2/3# of #P#.
Without your calculator, what is the fraction of #P# that oxygen gas exerts?

For ideal gases, the partial pressure is given by

#P_i = chi_iP#,

where:

The fraction of the total pressure #P# is given by
#chi_i = P_i/P#
And so, all we need to do is find the mols of each gas and calculate the mol fraction of #"H"_2#, i.e.:
#chi_(H_2) = (n_(H_2))/(n_(H_2) + n_(O_2))#
The mols of #"H"_2# are given by:
#4 cancel("g H"_2) xx "1 mol H"_2/(2.0158 cancel("g H"_2))#
#=# #"1.984 mols"#
The mols of #"O"_2# are given by:
#32 cancel("g O"_2) xx "1 mol O"_2/(31.998 cancel("g O"_2))#
#=# #"1.000 mols"#
Therefore, the fraction of #P# that #"H"_2# exerts is given by
#color(blue)(chi_(H_2)) = ("1.984 mols")/("1.984 mols H"_2 + "1.000 mols O"_2)#
#= color(blue)(0.665)#
This is about #color(blue)(2/3)# #color(blue)("of")# #color(blue)(P)#.
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Answer 2

Apply Dalton's law to find the partial pressure of oxygen: P(O2) = (moles of O2 / total moles) * total pressure. Calculate moles using the given masses and molar masses (H2 = 2 g/mol, O2 = 32 g/mol).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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