Given #K_"sp"# #ZnCO_3=1.46xx10^-10#, what is the #"ppm"# concentration of a saturated solution?

Answer 1

#S = 1.21xx10^-5M = 1.51xx10^-3(g/L)#

#ZnCO_3 rightleftharpoons Zn^(+2) + CO_3^(2-)# is a 1:1 ionization ratio. The solubility can be determined using #S = sqrt(Ksp)#

#S = sqrt(Ksp) = sqrt(1.46xx10^-10)M = 1.21xx10^-5M#

1.51x10^-3(g/L) = 1.21x10^-5(mol)/Lxx (125g)/"mol"

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Answer 2

Owen Ambrose

#"Solubility"_(ZnCO_3) = "1 ppm"#

We take into account the equilibrium reaction.

#ZnCO_3(s) stackrel(H_2O)rightleftharpoonsZn^(2+) + CO_3^(2-)#

And #K_(sp)=[Zn^(2+)][CO_3^(2-)]=1.46xx10^-10#

We let the #"Solubility"_(ZnCO_3) = x*mol*L^-1#

And thus #"Solubility"_(ZnCO_3)=sqrt(1.46xx10^-10)#

#=1.21xx10^-5*mol*L^-1#

Consequently, the solubility of zinc carbonate in grams

#-=1.21xx10^-5*mol*L^-1xx125.4*g*mol^-1~=1*mg*L^-1#, i.e. #"ppm"# concentrations.

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Answer 3

Ellie Andrews

The concentration of a saturated solution is 1.21 ppm.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.