# If #4.25 xx 10^3# #"g"# of gold was heated from #15.5^@ "C"# to #197.0^@ "C"#, how much heat was involved, and what is the molar enthalpy in #"kJ/mol"#? #C_P = "0.129 J/g"^@ "C"#?

The heat flow equation is to be used at constant atmospheric pressure:

where:

Thus, if we assume the specific heat capacity does not change in this temperature range, the heat absorbed is

At constant pressure, the heat flow is also related to the molar enthalpy:

Therefore, the enthalpy for this heating process at constant pressure is:

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The heat involved is 2.88 x 10^5 J, and the molar enthalpy is 64.6 kJ/mol.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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