How do we find the number of neutrons in a nuclide, given #Z#, and the isotopic mass?

Answer 1

The number of neutrons equals the #"isotopic mass"# LESS the #"atomic number"#, #Z#.

To a first approximation, the mass of the nuclide is the number of massive nuclear particles, i.e. the #"number of protons"# (which number defines the atomic number, #Z#) and the #"number of neutrons"#, which number defines the isotope.
By way of example, the most abundant element in the universe is hydrogen, #Z=1#. All hydrogen nuclei have the one PROTON present in their nuclei. A small percentage of hydrogen nuclei contain ONE neutron, a massive, neutrally charged particle, to give the #"deuterium isotope"#, #""^2H#; a smaller percentage of hydrogen nuclei contain TWO neutrons, a massive, to give the #"tritium isotope"#, #""^3H#.

The reported atomic mass of the majority of higher elements is the weighted average of the individual isotopes, since most elements contain multiple isotopes.

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Answer 2

The number of neutrons in a nuclide can be found by subtracting the atomic number (Z) from the isotopic mass (A). So, the number of neutrons (N) is calculated as N = A - Z.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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