Home > Chemistry > Writing Ionic Formulas

How do we formulate the reaction between aluminum and chlorine gas? What is the molar equivalence?

Answer 1

We wants to make #AlCl_3#.........

Aluminum metal comes from Group 13 of the Periodic Table; it typically forms the #Al^(3+)# cation on oxidation......Meanwhile chlorine comes from Group 17. It is typically reduced to give the chloride ion, #Cl^-#.

And so #Al^(3+) + 3xxCl^-# and we gets #AlCl_3# as the neutral salt; in the solid phase it is probably the chloro-bridged dimer, #{Cl_2Al}_2(mu"-"Cl)_2#....

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Cameron Andrews

The balanced chemical equation is: 2 Al(s) + 3 Cl2(g) -> 2 AlCl3(s). The molar equivalency is 2 moles of aluminum reacting with 3 moles of chlorine gas to produce 2 moles of aluminum chloride. Aluminum chloride is the product of the reaction between aluminum and chlorine gas.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.