What is the likely identity of a gas at #273.15# #K#, whose mass is #7.5*g#, and which exerts a pressure of #1*"bar"#?

Answer 1

Well, let's try to address the molar mass of the gas........we get a range of possibilities.........

#"STP"# specifies a temperature of #273.15 K#, and an absolute pressure of exactly #100* kPa, "1 bar"#.
#n=(PV)/(RT)=(1*cancel"bar"xx5.6*cancelL)/(8.314xx10^(-2)cancelL*cancel"bar"*cancel(K^-1)*mol^-1xx273.15*cancelK)#
#=0.247*(mol^-1)^-1=0.247*mol#
And thus #(7.5*g)/(0.247*mol)=30.3*g*mol^-1#.
The gas is likely the homonuclear diatomic #N_2# or #O_2#.

To identify the gas, more information is required.

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Answer 2

The likely identity of the gas at 273.15 K with a mass of 7.5 g and exerting a pressure of 1 bar is nitrogen (N2) according to the ideal gas law equation, PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature in Kelvin.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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