# A train is moving at a constant velocity of #"5 m/s"#. After it exists a tunnel, it starts to accelerate with an acceleration of #"9 m/s"^2# for #"5 s"#. What is the velocity of the train after #"5 s"# ?

To solve this, we can use the equation

where

Plugging in known values, we have

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To find the velocity of the train after 5 seconds of acceleration, you can use the formula:

[ v = u + at ]

Where:

- ( v ) is the final velocity
- ( u ) is the initial velocity
- ( a ) is the acceleration
- ( t ) is the time

Given:

- Initial velocity (( u )) = 5 m/s
- Acceleration (( a )) = 9 m/s²
- Time (( t )) = 5 s

[ v = 5 + (9)(5) ] [ v = 5 + 45 ] [ v = 50 ]

So, the velocity of the train after 5 seconds of acceleration is 50 m/s.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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