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What is the first step in forming #"CFC"#'s from #"CF"_3"Br"#?

Answer 1

Mateo Aguilar

This is what I believe ought to be done as the initial step:

#"CF"_3"Br" stackrel(hnu" ")(->) "F"_3"C" cdot + cdot"Br"#

which, because the bond was evenly split so that one electron went to each center, is homolytic cleavage.

The fragments then recombine in manners akin to radical halogenation reactions, both symmetric and asymmetric:

#2"F"_3"C"cdot -> "F"_3"C"-"CF"_3#

(trifluoromethyl radical combination)

#2"Br"cdot -> "Br"_2#

(two bromine radicals combined)

and perhaps we could obtain... if the homolytic cleavage was incomplete.

#"F"_3"C"cdot + "Br"cdot -> "CF"_3"Br"#

(reaction in reverse)

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Answer 2

Henry Antrim

The first step in forming CFCs (chlorofluorocarbons) from CF3Br (bromotrifluoromethane) involves the dissociation of CF3Br by ultraviolet radiation in the stratosphere. This leads to the release of a bromine atom, which then reacts with ozone (O3) to form bromine monoxide (BrO).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.