How many electrons in a #196*g# mass of sulfuric acid?

Answer 1

Approx. #3xx10^25# #"electrons"#.

In one MOLECULE of #H_2SO_4#, there are #2xx1(H)+16(S)+4xx8(O)=50# electrons in total.
But we have a molar quantity of #(196*g)/(98.08*g*mol^-1)=2*mol#. And given that there are #"Avogadro's number,"# #6.022xx10^23*"particles mol"^-1#, we have #N_Axx50*"electrons"#
#=3xx10^25# #"electrons"#............anyway, do this on your calculator and see if I have got the arithmetic right for once.
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Answer 2

To find the number of electrons in a 196 g mass of sulfuric acid, you would first need to determine the number of moles of sulfuric acid using its molar mass. Then, you would multiply the number of moles by Avogadro's number (6.022 x 10^23 electrons per mole) to find the number of electrons.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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