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What is the #"molality"# of a #200g# mass of sugar dissolved in a mass of #100g# of water?

Answer 1

Well, we can work out its #"molality"# directly.........

#"Molality"="Moles of solute"/"Kilograms of solvent"#

And here #"Molality"=((200*g)/(180.16*g*mol^-1))/(0.100*kg)=11.1*mol*kg#.

We would normally express concentration in the more familiar terms of #"molarity"#, where #"molarity"="Moles of solute (mol)"/"Volume of solution (L)"#.

Do you understand the distinction I'm trying to make? We would expect that the volume of solution would differ somewhat in each scenario (the difference might be slight!).

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Answer 2

Naomi Aronson

The molality of the solution is approximately 5.55 mol/kg.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

What is the #"molality"# of a #200*g# mass of sugar dissolved in a mass of #100*g# of water?

What is the #"molality"# of a #200g# mass of sugar dissolved in a mass of #100g# of water?