What is the molarity of a #0.28*mol# quantity confined to a volume of #2.6*L#?

Answer 1

#"Molarity"="Moles of solute"/"Volume of soluton"..............#

Thus, in this case..

#"Molarity"=(0.28*mol)/(2.6*L)=0.108*mol*L^-1............#

We can determine the necessary units of concentration using the quotient.

#"moles of solute per volume of solution"#, i.e. #mol*L^-1#.
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Answer 2

The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. Therefore, the molarity (M) of the solution is:

M = moles of solute / volume of solution (in liters)

Given: Number of moles of solute (n) = 0.28 mol Volume of solution (V) = 2.6 L

M = 0.28 mol / 2.6 L M ≈ 0.108 M

So, the molarity of the solution is approximately 0.108 M.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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