A gas enclosed in piston at #328.2K# occupies a volume of #3.60L#. How does the volume change when the gas is cooled to #303.2*K#?

Answer 1

We use old #"Charles' Law............"VpropT#

If #VpropT#, then #V=kT#; the equation assumes constant pressure, and a given quantity of gas. #T# is specified as #"absolute temperature"#.

If we solve for #k#, the #V/T=k#........

Additionally, given a constant gas volume and pressure:

#V_1/T_1=V_2/T_2#

#V_2=(3.60*L)/(328.2*K)xx303.2*K=3.3*L#.

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Answer 2

Ellie Andrews

The volume of the gas decreases when it is cooled from 328.2 K to 303.2 K.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

A gas enclosed in piston at #328.2*K# occupies a volume of #3.60*L#. How does the volume change when the gas is cooled to #303.2*K#?

A gas enclosed in piston at #328.2K# occupies a volume of #3.60L#. How does the volume change when the gas is cooled to #303.2*K#?