What is the #"molality"# of pure water?
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The formula for "molality" is ((1000g)/(18.01gmol^-1))/(1kg) =??mol*kg^-1.
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The molality of pure water is approximately 55.5 mol/kg, which means there are 55.5 moles of water per kilogram of solvent (water).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- Please guide me : i have 0.5 grams of solid waste sample. It is acid digested and then diluted to 500 ml. This is tested for chromium by atomic absorption and the conc came out to be .243 mg/l. what will be the actual concentration in the solid sample?
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