What is the #"molality"# of pure water?

Answer 1

Large...........#>50*mol*kg^-1#

#"Molality"="Moles of solute"/"Kilograms of solvent"#,
and so if we assume a #1*kg# mass of water,............(what is the volume?).........then

The formula for "molality" is ((1000g)/(18.01gmol^-1))/(1kg) =??mol*kg^-1.

And this value is quite comparable to water's #"molarity"#?
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Answer 2

The molality of pure water is approximately 55.5 mol/kg, which means there are 55.5 moles of water per kilogram of solvent (water).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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