For the reaction #4"XY"_3 + 7"Z"_2 -> 6"Y"_2"Z" + 4"XZ"_2#, what is the enthalpy change? The steps are shown below.

#"X"_2 + 3"Y"_2 -> 2"XY"_3#, #DeltaH_1 = -"320 kJ"#
#"X"_2 + 2"Z"_2 -> 2"XZ"_2#, #DeltaH_2 = -"140 kJ"#
#2"Y"_2 + "Z"_2 -> 2"Y"_2"Z"#, #DeltaH_3 = -"230 kJ"#

Question
Answer 1

#DeltaH_(rxn) = DeltaH_1' + DeltaH_2' + DeltaH_3' = ???#

(#DeltaH_i' ne DeltaH_i#.)

#-2(X_2 + 3Y_2 -> 2XY_3)#, #-2(DeltaH_1 = -"320 kJ")#

#2(X_2 + 2Z_2 -> 2XZ_2)#, #2(DeltaH_2 = -"140 kJ")#

#3(2Y_2 + Z_2 -> 2Y_2Z)#, #3(DeltaH_3 = -"230 kJ")#

#4XY_3 -> cancel(2X_2) + cancel(6Y_2)#, #DeltaH_1' = +"640 kJ"#

#cancel(2X_2) + 4Z_2 -> 4XZ_2#, #DeltaH_2' = -"280 kJ"#

#cancel(6Y_2) + 3Z_2 -> 6Y_2Z#, #DeltaH_3' = -"690 kJ"#

#"----------------------------------------------------"#

#4XY_3 + 7Z_2 -> 6Y_2Z + 4XZ_2#,

#color(blue)(DeltaH_(rxn) = DeltaH_1' + DeltaH_2' + DeltaH_3' = ???)#

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Answer 2
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