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In a #5*kg# mass of urea, what is the mass of nitrogen?

Answer 1

Serenity Allen

For a start, urea has a molecular formula of #CH_4N_2O#. I get under #2.5*kg# of nitrogen.

Urea has a formula of #O=C(NH_2)_2#, i.e. each mole of urea supplies two moles of (soluble?) nitrogen.

#"Moles of urea"=(5xx10^3*g)/(60.06*g*mol^-1)=83.25*mol#.

Consequently, a mass of................ exists.

#2xx83.25*molxx14.01*g*mol^-1=2333*g#

in relation to nitrogen.

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Answer 2

Owen Ambrose

Since there are two nitrogen atoms in each urea molecule, the molar mass of nitrogen in urea is 14.01 g/mol * 2 = 28.02 g/mol. As a result, the mass of nitrogen in 5 kg of urea is (28.02 g/mol / 60.06 g/mol) * 5 kg = 2.32 kg. The molar mass of urea (CO(NH2)2) is 60.06 g/mol.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.