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What mass of anhydrous salt is required to prepare a #50g# mass of #"acetic acid trihydrate"#, #H_3C-CO_2H3H_2O#?

Answer 1

Peyton Adams

You want approx. #30*g# of the anhydrous salt.

Sodium acetate trihydrate has a formula mass of #136.04*g*mol^-1#.

And thus a #50*g# mass is a molar quantity of..........

#(50*cancelg)/(136.04*cancelg*mol^-1)=0.368*1/(1/(mol))=0.368*mol.#

Now this is #0.368*mol# with respect to sodium and acetate ions, but #1.10*mol# with respect to water.

Thus, we determine the equivalent mass of the ANHYDROUS salt using the provided molar quantity:

#0.368*cancel(mol)xx82.03*g*cancel(mol^-1)=30.2*g#

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Answer 2

Natalie Anton

The molar mass of acetic acid trihydrate is ( 120.1 , \text{g/mol} ). Therefore, ( 50 , \text{g} ) of acetic acid trihydrate requires approximately ( 0.416 , \text{mol} ) of the compound. The mass of anhydrous salt required is approximately ( 49.96 , \text{g} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

What mass of anhydrous salt is required to prepare a #50*g# mass of #"acetic acid trihydrate"#, #H_3C-CO_2H*3H_2O#?

What mass of anhydrous salt is required to prepare a #50g# mass of #"acetic acid trihydrate"#, #H_3C-CO_2H3H_2O#?