How does chlorine gas react to give chloride and hypochlorite ions in BASIC solution?

Answer 1

#"This is a disproportionation reaction........."#

#Cl_2# is reduced to chloride, #Cl^-#:
#1/2stackrel(0)Cl_2 + e^(-) rarr stackrel(-I)Cl^(-)# #(i)#

and turned into hypochlorite through oxidation.

#1/2stackrel(0)Cl_2 +2HO^(-) rarr stackrel(+I)ClO^(-)+H_2O +e^(-)# #(ii)#
And OVERALL........#(i) + (ii):#
#Cl_2 +2HO^(-) rarr Cl^(-) + ClO^(-) +H_2O#

If the equation is to be regarded as a true representation of chemical reality—that is, physical reality—then it must be balanced in terms of charge and mass.

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Answer 2

The process of a disproportionation reaction in which chlorine gas is simultaneously reduced to chloride ions and oxidized to hypochlorite ions is as follows: Cl2 (g) + 2OH- (aq) → ClO- (aq) + Cl- (aq) + H2O (l). This reaction occurs in a basic solution and results in the formation of hypochlorite ions and chloride ions.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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