If #100*mL# of ammonia gas are decomposed into its constituent elements what volumes of dinitrogen, and dihydrogen would result?

Answer 1

Well, if we could decompose gaseous ammonia........to gives its constituent elements..........

#NH_3(g) rarr 1/2N_2(g) + 3/2H_2(g)#

And so at STP, if #100*mL# of ammonia are decomposed according to the given equation, #50*mL# of dinitrogen, and #150*mL# dihydrogen will result.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Noah Aldrich

According to the balanced chemical equation for the decomposition of ammonia (NH3) into its constituent elements (N2 and H2), the molar ratio between NH3 and N2 is 1:1, and the molar ratio between NH3 and H2 is 2:3. Given that 100 mL of NH3 gas is decomposed, we need to determine the volumes of N2 and H2 produced. Since the volume ratios are the same as the molar ratios, 100 mL of NH3 gas would produce 100 mL of N2 gas and (2/3) * 100 mL = 66.67 mL of H2 gas. Therefore, the volumes of dinitrogen and dihydrogen resulting from the decomposition of 100 mL of ammonia gas would be 100 mL and 66.67 mL, respectively.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.