#"6345 J"# of energy are required to raise the temperature of water from #22.6^@"C"# to #45.1^@"C"#. What is the mass of the water?

Question

Owen Ambrose · Accepted Answer

The mass of water is #"67.4 g"#.

Use the equation: #q=mcDeltat# where #q# is energy in Joules (J), #m# is mass, #c# is specific heat capacity, and #Deltat#, which is change in temperature. #Deltat=T_"final"-T_"initial"# The specific heat capacity of water, #c_"H2O"#, is not given. It is #4.184 "J"/("g"*^@"C")#. https://tutor.hix.ai Organize your information. Given #q="6345 J"# #c_"H2O"=4.184 "J"/("g"*^@"C")# #Deltat=("45.1"^@"C"-"22.6"^@"C")="22.5"^@"C"# Unknown: mass in grams Solution Rearrange the equation to isolate #m#. Substitute the given values into the equation and solve. #m=q/(cDeltat)# #m=(6345color(red)cancel(color(black)("J")))/(4.184color(red)cancel(color(black)("J"))/("g"*^@color(red)cancel(color(black)("C")))xx22.5^@color(red)cancel(color(black)("C")))="67.4 g H"_2"O"# (rounded to three significant figures)

Naomi Aronson · Answer

undefined The mass of the water is approximately 150 grams.