To completely combust a 5 mole quantity of glucose, how many moles of dioxygen are required?

Answer 1

Well first we write a stoichiometrically balanced equation...

#C_6H_12O_6(s) + 6O_2(g) rarr 6CO_2(g) + 6H_2O(l)#

Is there a stoichiometric balance here?

Therefore, it is evident that 30 moles of dioxygen gas are needed in order to completely burn 5 moles of glucose. What masses do these quantities represent?

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Answer 2

30 moles of dioxygen.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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