If #12*L# of hydrogen gas react with #12*L# of chlorine gas, what volume of #HCl(g)# will result?

Question

Naomi Aronson · Accepted Answer

The volume of a gas is equivalent to the number of molecules it contains under equivalent temperature and pressure. And thus we should get #22.4*L# #HCl(g)#.

We examine the response: #1/2H_2(g) + 1/2Cl_2(g) rarr HCl(g)#, correspondingly, #H_2(g) + Cl_2(g) rarr 2HCl(g)#, Given the opening statement, i.e. which is due to Avogadro, the volumes are proportional to the number of molecules each gas contains. Dihydrogen gas is present in HALF MOLAR proportion, and dichlorine is present in excess. And thus, given complete reaction, #11.2*L# of #H_2# reacts with #11.2*L# of #Cl_2# to give #22.4*L# #HCl(g)#. This whole thing is predicated on the stoichiometric equation.

Serenity Allen · Answer

undefined According to the balanced chemical equation for the reaction between hydrogen gas (H2) and chlorine gas (Cl2) to form hydrogen chloride gas (HCl), the volume of HCl produced would also be 12 L. This is because the stoichiometry of the reaction is 1:1, meaning for every one volume unit of hydrogen and chlorine gases reacted, one volume unit of hydrogen chloride gas is produced.