How is diethyl ether prepared from ethyl bromide and ethyl alcohol?
What about "ethyl alcohol" and "ethyl bromide" along with a small amount of non-nucleophilic base?
Naturally, you need to locate a helpful base.
Given the product's volatility and flammability, there would definitely be effective industrial preparation, carried out under very strict guidelines.
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Diethyl ether can be prepared from ethyl bromide and ethyl alcohol through an acid-catalyzed dehydration reaction. The reaction proceeds as follows:
[ \text{C}_2\text{H}_5\text{Br} + \text{C}_2\text{H}_5\text{OH} \xrightarrow{\text{H}_2\text{SO}_4} \text{C}_2\text{H}_5\text{OC}_2\text{H}_5 + \text{HBr} ]
Here, sulfuric acid (( \text{H}_2\text{SO}_4 )) serves as the catalyst for the reaction, leading to the formation of diethyl ether (( \text{C}_2\text{H}_5\text{OC}_2\text{H}_5 )) and hydrogen bromide (( \text{HBr} )).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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